Question

The equation of motion of a projectile is y =12x - 3/4x^2.Given that g=10 ms what is the range of the projectile

Answer 1

Horizontal Range of projectile means displacement covered by projectile in x - axis.

hence, during motion ,
initial level of projectile = final level of projectile .
hence, y = 0 for finding range

Here,
y = 12x - 3x²/4
put , y = 0

0 = 12x - 3x²/4

12x = 3x²/4

12×4 = 3x

x = 16 m

hence, range of projectile is 16 m

Answer 2

Answer:

16m

Step-by-step explanation:

Horizontal range= displacement covered by particle on x axis

we know that,

initial = final in projectile

therefore, y =0

put y=0 in given equation

$12x - \frac{3}{4} {x}^{2} = 0$

$12x = \frac{3}{4} {x}^{2}$

$12 \times 4 = \frac{3 {x}^{2} }{x}$

$48 = 3x$

therefore x= 16m