find the value of the polynomial x^2-3×+2 when(i)x=-1 and (ii)x=2?
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Answer:
i) 6
ii) 0
Step-by-step explanation:
x² - 3x + 2
i) x = 1
=> -1² - 3(-1) + 2
=> 1 + 3 + 2
=> 6
ii) x = 2
=> 2² - 3(2) + 2
=> 4 - 6 + 2
=> 0
Hope this helps
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