Question

find the value of the question ​

Answer 1

Step-by-step explanation:

$\sf \frac{sin3\alpha - sin\alpha}{{cos}^{2}\alpha - {sin}^{2}\alpha} \\ \\ \sf \longrightarrow \frac{cos(\frac{3\alpha +\alpha}{2})sin(\frac{3\alpha-\alpha}{2})}{cos2\alpha} \\ \\ \sf \longrightarrow \frac{cos(\frac{4\alpha}{2})sin(\frac{2\alpha}{2})}{cos2\alpha} \\ \\ \sf \longrightarrow \frac{cos2\alpha .sin\alpha}{cos2\alpha} \\ \\ \sf \longrightarrow sin\alpha$

❣️NIRANJAN45❣️

Answer 2

Answer:

sin3α−sinα

⟶

cos2α

cos(

2

3α+α

)sin(

2

3α−α

)

⟶

cos2α

cos(

2

4α

)sin(

2

2α

)

⟶

cos2α

cos2α.sinα

⟶sinα