Question

Find the value of the remainder, when x² +(a+b)x +ab is divided by (x+a).​

Answer 1

Answer:

Here, p(x)=x

3

+ax

2

+6x−a, and the zero of x−a is a

So, p(a)=a

3

+a×a

2

+6×a−a

=2a

3

+5a

So, by the Remainder Theorem, 2a

3

+5a is the remainder when x

3

+ax

2

+6x−a is divided by x−a.

Answer 2

Answer:

this is your ans...

Step-by-step explanation:

Here, p(x)=x

3

+ax

2

+6x−a, and the zero of x−a is a

So, p(a)=a

3

+a×a

2

+6×a−a

=2a

3

+5a

So, by the Remainder Theorem, 2a

3

+5a is the remainder when x

3

+ax

2

+6x−a is divided by x−a.