Find the value of the surface density for the infinitely charged plate if it is known that each two equipotential surfaces separated by 1m have potential difference of 5v
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Answer:
E=
2ϵ
o
σ
V=El
⟹l=
σ
2Vϵ
o
⟹l=
10
−7
2×5×8.85×10
−12
⟹l=8.85×10
−4
m
⟹l=0.88mm
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