find the value of the unknown X in the following diagram
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Step-by-step explanation:
(i) In ∆ABC,
x+50°+60°=180°
=>x+110°=180°
=>x=180°-110°=70°
therefore X=70°
(ii)In∆PQR,
90°+30°+x=180°
=>120°+x=180°
=>x=180°-120°=60°
therefore,X=60°
(iii)in ∆XYZ,
30°+110°+x=180°
=>140°+x=180°
=>x=180°-140°=40°
Therefore, X=40°
(iv)In the given triangle
=>50°+x+x=180°
=>50°+2x=180°
=>2x=180°-50°
=>2x=130°
=>x=130°/2=65°
therefore , X=65°
(v)in the given triangle
x+x+x=180°
=>3x=180°
=>x=180°/3
=>x=60°
therefore,X=60°
(vi)in the given triangle
=>x+2x+90°=180°
=>3x+90°=180°
=>3x=180°-90°
=>3x=90°
=>x=90°/3
=>x=30°
Therefore,X=30°
Used concept:-
The sum of all the three angles is equal to 180°
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