owing:
1. In the adjoining figure, what is. the area of the
each triang
square ABCD?
A
B
45°
D.
Cf6cm →E
(a)
(b)
(a) 36 cm2
(c) 83 cm?
(b) 18 cm
?
(d) can't be determined
on the
Answers
Answered by
1
Answer:
Given
ABCD is square
where AC=BD=42cm (diagonals)
we know length of a diagonal of a square whose each side is 'a' cm=2a
∴42=2a
∴a=4
That is AB=BC=CD=AD=4cm
Area of the square, ABCD=42=16cm2
Next, ΔADE
AD=4cm, AE=2.5cm=DE
This is an isoceles triangle
using Heron's formula
Area of ΔADE=s(s−a)(s−b)(s−c)
where s is the semi perimeter
Perimeter=AD+AE+DE=4+2.5+2.5=9cm
∴ semi perimeter=29=4.5cm
a=AD,b=AE,c=ED
Area of ΔADE=4.5(4.5−4)(4.5−2.5)(4.5−2.5)
=4.5×0.5×2×2=9
=3cm2
∴ Area of ABCDE=Area of ABCD+Area of ΔADE
=16+3=1
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0
Answer:
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