Question

Find the value of the x in the following equations​

Answer 1

$\large\sf\underline{Given\::}$

• $\sf\:\frac{x}{1-x}=\frac{-3}{2}$

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$\large\sf\underline{To\:find\::}$

• Value of x = ?

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$\large\sf\underline{Solution\::}$

$\sf\:\frac{x}{1-x}=\frac{-3}{2}$

• Cross multiplying

$\sf\implies\:2 \times x = -3(1-x)$

$\sf\implies\:2x = -3+3x$

• Transposing 3x to other side

Since 3x have +ve sign in the RHS when we transpose it to the other side it becomes -ve.

$\sf\implies\:2x - 3x = -3$

$\sf\implies\: - x = -3$

$\sf\implies\: \cancel{-} x = \cancel{-}3$

$\large{\mathfrak\red{\implies\:x\:=\:3}}$

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‎ ____________________

$\large\sf\underline{Verifying\:my\:answer\::}$

$\sf\:\frac{x}{1-x}=\frac{-3}{2}$

• Substituting x as 3 in the equation

$\sf\implies\:\frac{3}{1-3}=\frac{-3}{2}$

$\sf\implies\:\frac{3}{-2}=\frac{-3}{2}$

• Cross multiplying

$\sf\implies\:3 \times 2 = -3 \times -2$

$\sf\implies\:6 = 6$

${\sf{{\green{[\:Hence\:Verified\:]}}}}$

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!! Hope it helps !!