find the value of theta , if cos theta/ 1-sin theta + cos theta / 1+ sin theta = 4 , 0 < theta < 90
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cos theta/ 1-sin theta + cos theta / 1+ sin theta = 4
Cos theta[1/1-sin theta + 1/1+sin theta] =4
Cos theta[(1+sin theta+1-sin theta) /(1+sin theta) (1-sin theta) = 4
Cos theta[2/1-sin ^2theta]=4
Cos theta[2/cos^2 theta] =4
Cos theta/cos^2 theta=4/2
1/cos theta=2
Cos thetha=1/2
So theta = 60°
Cos theta[1/1-sin theta + 1/1+sin theta] =4
Cos theta[(1+sin theta+1-sin theta) /(1+sin theta) (1-sin theta) = 4
Cos theta[2/1-sin ^2theta]=4
Cos theta[2/cos^2 theta] =4
Cos theta/cos^2 theta=4/2
1/cos theta=2
Cos thetha=1/2
So theta = 60°
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