Question

Find the value of theta where theta is smaller than 90 degree and greater than zero degree:
1) tan3 θ=1
2) tan raised to 2 θ= 1/3
3) tan raised to 3 θ= 1

Answer 1

Answer:

I am using a in place of theeta

tan3a=1

tan3a=tan45

3a=45

a=15

2.tan2a=1/3

tan squarea=(1/√3)square

tan a=1/√3

tan a=tan 30

a=30

3.tan cube theeta= 1 cube

tan cube theeta= (tan45)^3

tan theeta = tan 45

theeta=45