Chemistry, asked by rocky293, 10 months ago

pls ans .fast....XD

Attachments:

Answers

Answered by cosmiccreed

Answer:

given: 1.41 g/mL HNO3 solution

the solution is 69% HNO3

1. calculate the mass of HNO3 in the solution

= 1.41 g/ml x 69%

= 0.9729 g/ml

2. convert the answer in 1 to mole quantity by dividing it with the molar mass of HNO3 which is 63 g/mol

= 0.9729 g/ml divided 63 g/mol

= 0.01544 mol/ml

3. Since molar quantity is expressed as mole per L, you need to multiply the answer in 2 with 1000 (1L = 1000ml)

= 0.01544 mol/ml X 1000

= 15.44 M

C: 12

H: 1

O: 16

So the molecular weight of the sugar is 12 x 12 + 22 x 1 + 11 x 16 = 342. So 20 grams is 20 / 342 = .058 moles. If the solution contains 2 liters, then the concentration is .058 / 2 = .029 mol / L

please

Molarity

=Moles of solute

Volume of solution (in litres)

For given solution

0.25 M=n2.5 L

n = 0.625 moles

0.625 moles

of methanol is needed.

Molar mass of methanol

(CH3OH)=32 g/mol

• Mass of methanol needed=0.625mol×32 gmol=20 g

Density of methanol=0.793 kg/L=793 g/L

Volume=MassDensity

• Volume of methanol needed=20 g

793 g/L=0.0252 L=25.2 mL

Answered by Anonymous

Answer :D

(1). The density of the solution is 1.41 g/mL.

1000 g of the solution will have a volume = Mass/Density = 1000/1.41 = 709 ml

The mass per cent of nitric acid is 69%

1000 g of the solution will have 1000 × (69/100) = 690 g of nitric acid

The molarity of solution is Mass of nitric acid ÷ (Molar mass of nitric acid × Volume of solution) = 690 ÷ (63 × 709) = 0.0155 M

(2). molarity = number of mole of solute ÷ volume of solvent in litres

0.25 = number of mole of methanol ÷ 2.5

no. of mole of methanol = 0.25 × 2.5 = 0.625 mole

weight of methanol = no. of mole of methanol × molecular weight of methanol

= 0.625 × 32

= 20 gram

weight of methanol = 20 ÷ 1000 kg

volume = weight of methanol/density

= (20/1000) ÷ 0.793

= 20 ÷ 793

= 0.025 litre

(3). To the nearest 0.1, the molecular weights of each element are:

C: 12

H: 1

O: 16

So the molecular weight of the sugar is 12 x 12 + 22 x 1 + 11 x 16 = 342.

So 20 grams is 20 / 342 = 0.058 moles.

If the solution contains 2 liters, then the concentration is 0.058 / 2 = 0.029 mol / L

$<html> <head> <style> h1{ text-transform:uppercase; margin-top:90px; text-align:center; font-family:Courier new,monospace; border:3px solid rgb(60,45,8); border-top:none; width:67%; letter-spacing:-6px; box-sizing:border-box; padding-right:5px; border-radius:6px; font-size:35px; font-weight:bold; } h1 span{ position:relative; display:inline-block; margin-right:3px; } @keyframes shahir{ 0% { transform: translateY(0px) rotate(0deg); } 40% { transform: translateY(0px) rotate(0deg); } 50% { transform: translateY(-50px)rotate(180deg);; } 60% { transform: translateY(0px)rotate(360deg);; } 100% { transform: translate(0px)rotate(360deg);; }} h1 span { animation: shahir 3s alternate infinite linear; } h1 span:nth-child(1) {color:pink; animation-delay: 0s; } h1 span:nth-child(2) {color:lightmaroon; animation-delay: 0.2s; } h1 span:nth-child(3) {color:red; animation-delay:0s; } h1 span:nth-child(4) {color:lightgreen; animation-delay: 0.4s; } h1 span:nth-child(5) {color:blue; animation-delay: 0.5s; } h1 span:nth-child(6) {color:purple; animation-delay: 0.3s; } </style> <meta name="viewport" content="width=device-width" > </head> <body> <center> <div> <h1> T H A N K S </h1> </div> </center> </body> </html>$

$<svg class= "heart" viewBox= "-2 -2 98.6 90.81"> <title>Corazon</title> <text x=8 y=22 dx= "0 0 0 0 0 0 0" dy= "2 -8 -2 -1 1 2 4 "style= "font: bold .7em arial; fill: red;"> killer <tspan x=60 y=22 style= "font: bold .7em arial; fill: blue;">9999</tspan> <tspan x= 10 dy= 15 style= "font: bold .6em arial; fill: navy;"> people with 75% at least</tspan> <tspan x= 25 dy= 10 style= "font: bold .6em arial; fill: navy;">Goodness can</tspan> <tspan x= 35 dy= 10 style= "font: bold .6em arial; fill: navy;">see the</tspan> <tspan x= 37 dy= 10 style= "font: bold .5em arial; fill: red;">HEART</tspan> <animate attributeType="XML" attributeName="visibility" from="visible" to="hidden" dur="9.2s" begin="0s" /> </text> <path stroke= "firebrick" stroke-width= "3" d= "M86.81,8.15a27.79,27.79,0,0,1,0,39.33L47.48,86.81,8.15,47.48A27.81,27.81,0,0,1,47.48,8.15,27.79,27.79,0,0,1,86.81,8.15Z"/> </svg><style>body { display: grid; min-height: 100vh; justify-content: center; align-content: center; background: repeating-linear-gradient(circle, white, yellow, red); background: repeating-radial-gradient(circle, white, yellow, red);}.heart { width: 250px; animation: heart-beat .5s 4.85s infinite ease-in-out alternate;}@keyframes heart-beat { to{ transform: scale(1.05); }}path { fill: none; stroke-dasharray: 286; stroke-dashoffset: 286; animation: heart-path 5s forwards; .ocultarText: color:transparent ;}@keyframes heart-path { 99% { stroke-dashoffset: 0; fill: none; } 100% { fill: firebrick; }}</style>$

Previous Question

Next Question

pls ans .fast....XD ​

Answers

Answer :D

(1). The density of the solution is 1.41 g/mL.

1000 g of the solution will have a volume = Mass/Density = 1000/1.41 = 709 ml

The mass per cent of nitric acid is 69%

1000 g of the solution will have 1000 × (69/100) = 690 g of nitric acid

The molarity of solution is Mass of nitric acid ÷ (Molar mass of nitric acid × Volume of solution) = 690 ÷ (63 × 709) = 0.0155 M

(2). molarity = number of mole of solute ÷ volume of solvent in litres

0.25 = number of mole of methanol ÷ 2.5

no. of mole of methanol = 0.25 × 2.5 = 0.625 mole

weight of methanol = no. of mole of methanol × molecular weight of methanol

= 0.625 × 32

= 20 gram

weight of methanol = 20 ÷ 1000 kg

volume = weight of methanol/density

= (20/1000) ÷ 0.793

= 20 ÷ 793

= 0.025 litre

(3). To the nearest 0.1, the molecular weights of each element are:

C: 12

H: 1

O: 16

So the molecular weight of the sugar is 12 x 12 + 22 x 1 + 11 x 16 = 342.

So 20 grams is 20 / 342 = 0.058 moles.

If the solution contains 2 liters, then the concentration is 0.058 / 2 = 0.029 mol / L

pls ans .fast....XD