Chemistry, asked by rocky293, 9 months ago

pls ans .fast....XD

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Answered by cosmiccreed

Answer:

given: 1.41 g/mL HNO3 solution

the solution is 69% HNO3

1. calculate the mass of HNO3 in the solution

= 1.41 g/ml x 69%

= 0.9729 g/ml

2. convert the answer in 1 to mole quantity by dividing it with the molar mass of HNO3 which is 63 g/mol

= 0.9729 g/ml divided 63 g/mol

= 0.01544 mol/ml

3. Since molar quantity is expressed as mole per L, you need to multiply the answer in 2 with 1000 (1L = 1000ml)

= 0.01544 mol/ml X 1000

= 15.44 M

C: 12

H: 1

O: 16

So the molecular weight of the sugar is 12 x 12 + 22 x 1 + 11 x 16 = 342. So 20 grams is 20 / 342 = .058 moles. If the solution contains 2 liters, then the concentration is .058 / 2 = .029 mol / L

please

Molarity

=Moles of solute

Volume of solution (in litres)

For given solution

0.25 M=n2.5 L

n = 0.625 moles

0.625 moles

of methanol is needed.

Molar mass of methanol

(CH3OH)=32 g/mol

• Mass of methanol needed=0.625mol×32 gmol=20 g

Density of methanol=0.793 kg/L=793 g/L

Volume=MassDensity

• Volume of methanol needed=20 g

793 g/L=0.0252 L=25.2 mL

Answered by Anonymous

Answer :D

(1). The density of the solution is 1.41 g/mL.

1000 g of the solution will have a volume = Mass/Density = 1000/1.41 = 709 ml

The mass per cent of nitric acid is 69%

1000 g of the solution will have 1000 × (69/100) = 690 g of nitric acid

The molarity of solution is Mass of nitric acid ÷ (Molar mass of nitric acid × Volume of solution) = 690 ÷ (63 × 709) = 0.0155 M

(2). molarity = number of mole of solute ÷ volume of solvent in litres

0.25 = number of mole of methanol ÷ 2.5

no. of mole of methanol = 0.25 × 2.5 = 0.625 mole

weight of methanol = no. of mole of methanol × molecular weight of methanol

= 0.625 × 32

= 20 gram

weight of methanol = 20 ÷ 1000 kg

volume = weight of methanol/density

= (20/1000) ÷ 0.793

= 20 ÷ 793

= 0.025 litre

(3). To the nearest 0.1, the molecular weights of each element are:

C: 12

H: 1

O: 16

So the molecular weight of the sugar is 12 x 12 + 22 x 1 + 11 x 16 = 342.

So 20 grams is 20 / 342 = 0.058 moles.

If the solution contains 2 liters, then the concentration is 0.058 / 2 = 0.029 mol / L

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Answer :D

(1). The density of the solution is 1.41 g/mL.

1000 g of the solution will have a volume = Mass/Density = 1000/1.41 = 709 ml

The mass per cent of nitric acid is 69%

1000 g of the solution will have 1000 × (69/100) = 690 g of nitric acid

The molarity of solution is Mass of nitric acid ÷ (Molar mass of nitric acid × Volume of solution) = 690 ÷ (63 × 709) = 0.0155 M

(2). molarity = number of mole of solute ÷ volume of solvent in litres

0.25 = number of mole of methanol ÷ 2.5

no. of mole of methanol = 0.25 × 2.5 = 0.625 mole

weight of methanol = no. of mole of methanol × molecular weight of methanol

= 0.625 × 32

= 20 gram

weight of methanol = 20 ÷ 1000 kg

volume = weight of methanol/density

= (20/1000) ÷ 0.793

= 20 ÷ 793

= 0.025 litre

(3). To the nearest 0.1, the molecular weights of each element are:

C: 12

H: 1

O: 16

So the molecular weight of the sugar is 12 x 12 + 22 x 1 + 11 x 16 = 342.

So 20 grams is 20 / 342 = 0.058 moles.

If the solution contains 2 liters, then the concentration is 0.058 / 2 = 0.029 mol / L

pls ans .fast....XD