find the value of this
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hey mate
here is your answer
let √6+√6 recurring be x
hence
√(6+x)=x
squaring both sides we get
6+x=x²
=>x²-x-6=0
=>x²-3x+2x-6=0
=>(x-3)(x+2)=0
thus x=3
hence the answer is 3
#be brainly
here is your answer
let √6+√6 recurring be x
hence
√(6+x)=x
squaring both sides we get
6+x=x²
=>x²-x-6=0
=>x²-3x+2x-6=0
=>(x-3)(x+2)=0
thus x=3
hence the answer is 3
#be brainly
Anonymous:
thanks
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