Question

find the value of two third lifetime of a first order reaction (chemistry class 12,chemical kinetics)

Answer 1

Two-third life of a reaction means that, two-third of the reaction has completed in time t.

t can be calculated as:

at t = t2/3, the concentration of reactant left will be = [R]o-2/3[R]o = 1/3[R]o.

or

at time t=0, [Ro]

at time t2/3=[Ro]*2/3

since t2/3=2.303/k* log([Ro]*3/[Ro]2)

now solve it, you will get the answer....:)

Answer 2

Answer:

Two-third life of a reaction means that, two-third of the reaction has completed in time t.

t can be calculated as:

at t = t2/3, the concentration of reactant left will be = [R]o-2/3[R]o = 1/3[R]o.

or

at time t=0, [Ro]

at time t2/3=[Ro]*2/3

since t2/3=2.303/k* log([Ro]*3/[Ro]2)