Question

find the value of unknown quantities from each of the following​

Answer 1

Answer:

A)

In ◇ABD

AD=BD

therefore/_B = /_BAD =25⁰

(Angles opposite to equal sides are equal)

Similarly

/_C = /_CAE= 20⁰

by angle sum property

<A+<B+<C=180⁰

20+25+x + 20+25=180⁰

90+x=180⁰

X=90⁰

2)In ◇ADE

Apply angle sum property to find X

and for ◇AEC

find the base angel using Lenier pair method and then apply Angle sum property. to ◇AEC.

3)In◇ABD

Apply Angle sum property to find Y

60⁰+90⁰+Y=180⁰

Samilarly for ◇AEC

4)Similar to Q1

Answer 2

Answer:

1. sum of all angles of triangle is equal to 180 degree

●each side of a triangle is 60 degree

sum of angles given in figure=25+20

=45

☆value of x=60-45

=15 degree

2. sum of all angles of triangle is equal to 180 degree

sum of angles=80+75

=155 degree

☆value of x=180-155

=25 degree

• value of angle E

=180 degree-75 degree

105 degree

☆value of y

=105+45+y=180 degree

=150+y=180

y=180-150

y=30 degree