Question

find the value of va-vb​

Answer 1

Solution:

• In order to find out the potential difference between points A and B, we will start noting the potential drops from point A and end at point B.

$\sf V_{A} + (2 \times i) - 5 + (1 \times i) + 2 = V_{B}$

• putting i = 2 amp.

$\sf \implies V_{A} + (2 \times 2) - 5 + (1 \times 2) + 2 = V_{B}$

$\sf \implies V_{A} + 4 - 5 + 2 + 2 = V_{B}$

$\sf \implies V_{A} + 3 = V_{B}$

$\sf \implies V_{A} - V_{B} = - 3 \: volts$

So, potential difference at point A and B is -3 Volts.