Question

Find the value of (x-1/x)=? If(x^2+1/x^2)=88

Answer 1

$\\ \\ {x}^{2} + \frac {1}{{x}^{2}} = 88 \\ \\ {x}^{2} + \frac {1}{{x}^{2}} - 2 \times x \times \frac {1}{x} = 88 - 2 \times x \times \frac {1}{x} \\ \\ {(x-\frac {1}{x})}^{2} = 86 \\ \\\ x - \frac {1}{x} = \sqrt{86}$