Replace * by the smallest no. so that :
871*45 is divisible by 9 & 534*0 divisible by 18
Answers
871245 ÷ 9 = 96805
53460 ÷ 18 = 2970
The value of * is 2 when 871*45 is divisible by 9.
The value of * is 6 when 534*0 divisible by 18.
Step-by-step explanation:
Given : 871*45 is divisible by 9 & 534*0 divisible by 18.
To find : Replace * by the smallest number ?
Solution :
Divisibility by 9,
When the sum of its digit is divisible by 9 then the number is divisible by 9.
So, 8+7+1+*+4+5 = 25+*
Put *=1,
25+1=26 not divisible by 9
Put *=2,
25+2=27 it is divisible by 9.
So, Here the smallest value of * is 2.
Divisibility by 18,
If it is an even number AND the sum of its digits is divisible by 9.
As last digit is 0 it is an even number.
Now, check for divisibility of 9.
As 5+3+4+*+0 = 12+*
Put *=1,
12+1=13 not divisible by 9
Put *=2,
12+2=14 not divisible by 9.
Put *=3,
12+3=15 not divisible by 9.
Put *=4,
12+4=16 not divisible by 9.
Put *=5,
12+5=17 not divisible by 9.
Put *=6,
12+6=18 it is divisible by 9.
So, Here the smallest value of * is 6.
#Learn more
Replace the star (*) by the smallest number, so that 78*96 is divisible by 9
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