find the value of x
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Answer:
the value of x of rhombus ABCD is 96°
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Given: ABCD is any rhombus.
AC is its diagonal.
To find the value of x
DCA=CAB...... {alternate angles}
But CAB=45°
Therefore, DCA=45°
DCA+BCA=180°....... {angles in linear pair}
45°+BCA=180°
BCA=180°-45°
BCA=135°
A+X+C=180°..... {angle sum property
of triangle.}
45°+X+135°=180°
180°+X= 180°
X= 180°-180°
X= 0°
......(hence solved)
hope it may help you.
Please mark it as a brainliest.
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