Math, asked by hrstchtrvd, 10 months ago

find the value of x​

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Answered by sukhdeep1440p2rbs3
2

Step-by-step explanation:

i. angle eba=120

angle ABC=180-120(Lp)

ABC=60

angle acd=110

angle acb=180-110(LP)

=70

60+70+x=180 (angle sum)

130+×=180

x=50

ii. angle eab=120

angle bac=180-120

=60

angle acd=112

angle acb =180-112=68

180=68+60+x

x=180-128

x=52

Hope it helps you

Answered by Pathenium
0

Answer:

In fig 1,

In triangle ABC,

ABE+ABC=180° {linear pair}

120°+ABC=180°

ABC=60°

Similarly,

ACB=70° {linear pair}

In triangle ABC,

ABC+ACB+x=180° {angle sum prop. of a ∆}

70°+60°+x=180°

x=180°-130°

x=50°

In fig 2,

In triangle ABC,

BAC=180°-BAE=180°-120°=60° {linear pair}

Similarly,

ACB=68° {linear pair}

In triangle ABC,

x+BAC+ACB=180° {angle sum prop. of a ∆}

x=180°-60°-68°

x=52°

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