find the value of x
(2)^7x-5 =(32)^x-7
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Answered by
2
Answer:
(2)^(7x-5)=(32)^(x-7)
=> (2)^(7x-5)=(2)^5(x-7)
=> 7x-5=5(x-7)
=> 7x-5=5x-35
=> 7x-5x= -35+5
=> 2x= -30
=> x= -30/2
=> x= -15
Answered by
2
Answer:
the value of x become 13.something
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