Math, asked by nisha9024, 7 months ago

find the value of x^2 if x= (-3/7)^5÷(11/4)^0

Answers

Answered by sarbajitdas029
2

Answer:

x =  ({ - 3 \div 7})^{5}  \div  ({11 \div 4})^{0}  \\ x = ( - 243 \div 16807) \div 1 \\  x  {}^{2} = ( { - 243 \div 16807})^{2}   \\ x { }^{2}  = 0.000209(approximately)

Answered by Anonymous
0

Answer:

kya koi mujhe bataenge ki main apni iss I'd ko kaise chalaoon

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