Question

Find the value of (x^2 + y^2) if xy= -15 and x-y = 6​

Answer 1

Answer:

576

Step-by-step explanation:

Given,

x - y = 6

xy= 20

NOW,

we know that (x-y)^2 = x^2 + y^2 - 2xy

now substitute,

6^2 = x^ 2+ y^2 - 2(20)

36= x^2 + y^2 - 40

x^2 + y^2 = 76 - (1)

now we know that, x^3 - y^3 = (xy)(x^2+y^2+xy) - (2)

so now substitute value of x-y, xy, equation (1) in equation (2)

x^3 - y^3 = 6 (76+ 20)

= 6(96)

= 576

therefore, x^3-y^3 = 576

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Answer 2

Answer:

DOnt

Step-by-step explanation: