find the value of x
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in this equation X will be 128°
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Step-by-step explanation:
IN ∆ABC
∆B=40°
∆A=30°
BY ANGLE SUM PROPERTY OF TRIANGLE,WE GET
∆ABC+∆BAC+∆ACB=180°
40°+30°+∆ACB=180°
∆ACB=180°-70°
∆ACB=110°
OR,ECB=110°
NOW,BCD IS A STRAIGHT LINE.
SO, BCD=180°
∆ECD & ∆ECB ARE LINEAR PAIRS.
SO, ∆ECD+∆ECB=180°
THEREFORE,∆ECD+110°=180°
SO,∆ECD=180°-110°
∆ECD=70°
NOW,∆EDC=50°
BY ANGLE SUM PROPERTY OF TRIANGLE,WE GET
∆ECD+∆EDC+∆CED=180°
70°+50°+∆CED=180°
∆CED=180°-120°
∆CED=60°
NOW AEC IS A STRAIGHT LINE
SO, AEC=180°
∆AED & ∆CED ARE LINEAR PAIRS.
SO,∆AED+∆CED=180°
X+60°=180°
X=180°-60°
X=120°
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