Question

Find the value of x :243×3^x+5+(3^x)^2/3^2×3^x-3^12 = 3^6x-62​

Answer 1

Step-by-step explanation:

Given, 3

x−y

=27 and 3

x+y

=243

3

x−y

=3

3

3

x+y

=3

5

Takin log to the base 3 on both sides for both the equations

x−y=3 and x+y=5

Adding them,

x−y+x+y=8

2x=8

x=4

Thus, 4−y=3

y=1