Question

find the value of x

Answer 1

Given Equation is :

$(\frac{3}{4} )^6 * ( \frac{16}{9})^5$ = $( \frac{4}{3}) ^{x + 2}$

$\frac{3^6 * 16^5}{4^6 * 9^5}$ = $(\frac{4}{3}) ^{x + 2}$

$\frac{3^6 * (2^4)^5}{(2^2)^6 * (3^2)^5} = (\frac{4}{3}) ^{x + 2}$

$\frac{3^6 * 2^{20} }{ 2^{12} * 3^{10} } = (\frac{4}{3}) ^{x + 2}$

$\frac{2^8}{3^4} = ( \frac{4}{3}) ^{x+2}$

$\frac{256}{81} = (\frac{4}{3}) ^{x + 2}$

$(\frac{4}{3})^4 = (\frac{4}{3}) ^{x + 2}$

4 = x + 2

x = 2.


Hope this helps!

Answer 2

Hi,

Please see the attached file!

Thanks