The speed of a train is reduced from 60 km/h. the driver exceeds the speed 12km/hr what is the percentage gain
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Answered by
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Hey there,
%gain=gain/initial speed*100
12/60*100=20%
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
%gain=gain/initial speed*100
12/60*100=20%
PLEASE MARK AS BRAINLIEST IF HELPFUL!!!
Answered by
0
Hlo Every one this is the answer hope it will help you
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