find the value of x.
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1
x²+2x+1=0
x²+x+x+1=0
x(x+1)+1(x+1)=0
(x+1)(x+1)=0
x= -1,-1
x²+x+x+1=0
x(x+1)+1(x+1)=0
(x+1)(x+1)=0
x= -1,-1
Answered by
0
x^2 + 2x +1 = 0
x^2 +(1+1)x +1 = 0
x^2 +x +x +1 =0
x(x +1) +1(x+1) = 0
(x+1)(x+1) = 0
then , x = -1
i hope this will help you
-by ABHAY
x^2 +(1+1)x +1 = 0
x^2 +x +x +1 =0
x(x +1) +1(x+1) = 0
(x+1)(x+1) = 0
then , x = -1
i hope this will help you
-by ABHAY
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