find the value of x
3√(3x-2)=4
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3√(3x-2)=4
√(3x-2)=4/3
(3x-2)=(4/3)^2
(3x-2)=16/9
3x=16/9+2
3x=34/9
x=34/9*3
x=1.25
√(3x-2)=4/3
(3x-2)=(4/3)^2
(3x-2)=16/9
3x=16/9+2
3x=34/9
x=34/9*3
x=1.25
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