Question

find the value of x
(-3)^x × (-3)^2x = (-3)^-9

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Answer 1

Answer:

(5÷3)^-9 => (3÷5)^9 by reciprocal to change negative to positive power

(5÷3)^-9 => (3÷5)^9 by reciprocal to change negative to positive power(3÷5)^5+9 = (3÷5)^2x

(5÷3)^-9 => (3÷5)^9 by reciprocal to change negative to positive power(3÷5)^5+9 = (3÷5)^2x5+9 =2x the base are same so, add the power

(5÷3)^-9 => (3÷5)^9 by reciprocal to change negative to positive power(3÷5)^5+9 = (3÷5)^2x5+9 =2x the base are same so, add the power14 = 2x

(5÷3)^-9 => (3÷5)^9 by reciprocal to change negative to positive power(3÷5)^5+9 = (3÷5)^2x5+9 =2x the base are same so, add the power14 = 2xx=14/2

(5÷3)^-9 => (3÷5)^9 by reciprocal to change negative to positive power(3÷5)^5+9 = (3÷5)^2x5+9 =2x the base are same so, add the power14 = 2xx=14/2x=7

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Answer 2

${ - 3}^{x} \times { - 3}^{2x} = { - 3}^{ - 9} \\ = > { - 3}^{x + 2x} = { - 3}^{ - 9} \\ = > x + 2x = - 9 \\ = > 3x = - 9 \\ = > x = \frac{ - 9}{3} \\ = > x = - 3$

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