find the value of x^3 + y^3 + 15xy + 125, if x+y = 5
Answers
Answered by
1
(x+y) = 5
(x+y)^3 = 5^3
x^3+y^3+3xy(x+y)= 125
x^3+y^3+15xy-125 = 0
adding 250 both sides
x^3+y^3+15xy-125+250=+250
x^3+y^3+15xy+125=250
(x+y)^3 = 5^3
x^3+y^3+3xy(x+y)= 125
x^3+y^3+15xy-125 = 0
adding 250 both sides
x^3+y^3+15xy-125+250=+250
x^3+y^3+15xy+125=250
anshaj0001:
question is asking +125
Answered by
2
Hey Angel ...
--> x = y - 5 ;
--> ( x³ + y³ ) + 15xy + 125
= ( x + y )³ - 3xy( x + y ) + 15xy + 125 --->[ ( x + y )³ = x³ + y³ + 3xy( x + y )]
= ( 5 )³ - 3*5*xy + 15xy + 125
= 125 - 15xy + 15xy + 125
= 250 √√
Hence, ( x³ + y³ ) + 15xy + 125 = 250
^_^ Hope this helps ...
--> x = y - 5 ;
--> ( x³ + y³ ) + 15xy + 125
= ( x + y )³ - 3xy( x + y ) + 15xy + 125 --->[ ( x + y )³ = x³ + y³ + 3xy( x + y )]
= ( 5 )³ - 3*5*xy + 15xy + 125
= 125 - 15xy + 15xy + 125
= 250 √√
Hence, ( x³ + y³ ) + 15xy + 125 = 250
^_^ Hope this helps ...
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