Find the value of x^3+ y^3
+ 15xy – 125 if x + y = 5.
Answers
Answered by
8
x+y=5
cubing both side,
(x+y)^3=x^3+y^3+3xy(x+y);
Putting the value of x+y;
125=x^3+y^3+3xy(5)
125=x^3+y^3+15xy
Thus,
x^3+y^3+15xy-125=0
cubing both side,
(x+y)^3=x^3+y^3+3xy(x+y);
Putting the value of x+y;
125=x^3+y^3+3xy(5)
125=x^3+y^3+15xy
Thus,
x^3+y^3+15xy-125=0
Answered by
4
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x+y=5
cubing on both sides
(x+y)^3=125
x^3+y^3+3xy(x+y)=125
x^3+y^3+3xy(5)=125. (Since x+y=5)
x^3+y^3+15xy=125
Thus
x^3+y^3+15xy-125=0
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