Question

Find the value of x,3x+5,x+10​

Answer 1

Step-by-step explanation:

(x+10)+(3x+5)+x =180 (linear pairs)

x+10+3x+5+x =180

5x+15 = 180

5x= 180 -15

5x= 165

x = 165/5

x= 33

Answer 2

Given:

∠DOA= x+10°

∠DOC=(3x+5)

∠COB=x

To find:

Value of x=?

Solution:

$\begin{gathered}\\ \sf\longmapsto ∠DOA+∠DOC+∠COB=180°[Linear \:pair]\end{gathered}$

• Putting values

$\begin{gathered}\\ \sf\longmapsto (x+10)+(3x+5)+(x)=180°\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 5x+15=180°\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 5x=180°-15°\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto 5x=165°\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto x=33°\end{gathered}$

∠DOA=x+10

=33+10

=44°

∠DOC=3×x+5

=3×33+5

=99+5

=104°

∠COB=x

=33°

Hence, the values of ∠DOA, ∠DOC & ∠COB are 44°,104° & 33° respectively..