Question

In triangle ABC, a median AP is drawn. Is AB + BC + CA > 2AP​

Answer 1

Answer:

So, in the triangle ABC. We have sub triangles ABM and AMC. Using the inequality of the triangle that the sum of any two sides is always greater than or equal to the third side. Hence AB+BC+CA>2AM is proved to be true.

Step-by-step explanation:

Answer 2

Answer:

yes

Step-by-step explanation:

In triangle ABC, a median AP is drawn. Is AB + BC + CA > 2AP is true