Question

Find the value of X.

Answer 1

Answer:

The energy initially stored by the capacitor is 1/2 C*V^2 or Q^2 / 2*C

When the plate separation is doubled, the charge remains constant and the capacitance is halved. The work done in separating the plates is the difference in energy stored: this is

Q^2 / 2*0.5*C - Q^2 / 2*C This represents double the initial energy less the initial energy. The work done in adding this energy is Q^2 / 2*C

Assigning values: ( 2*10–4 )^2 / ( 2* 10 *10^-6 ) = 2 mJ

Answer 2

Step-by-step explanation:

$◆ A_N_S_W_E_R ◆$

Refer to the above attachment ⬆️⬆️.