find the value of x...
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2
q1
angle aoc=4x
angle cod=5x
angle dob=6x
by adding the three angles ,
AOC+COD+DOB=180
Now we assume the values
4x + 5x + 6x=180
15x=180
×=180÷15
x= 12
aoc=4x = 48
cod= 5x= 60
dob= 6x= 72
you can do the otger sum with a similar method
angle aoc=4x
angle cod=5x
angle dob=6x
by adding the three angles ,
AOC+COD+DOB=180
Now we assume the values
4x + 5x + 6x=180
15x=180
×=180÷15
x= 12
aoc=4x = 48
cod= 5x= 60
dob= 6x= 72
you can do the otger sum with a similar method
Answered by
2
in the first question we have 4 x 5 x + 6 x we know that these are forming a linear pair because they are on a straight line so we have 4 x + 5 x + 6 X equal to 180 degree which is equal to 15 X equal to 180 degree and hence the value of x is 180 / 15 equal to 32
SukhdeepSingh:
then finally you did what I wanted thanks a lot
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