Sum of digits of least multiple of 13 when divide by 6,8 and 12 leaves remainder 5 , 7, 11
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LCM of 4, 5, 6, 7 and 8 = 840.
Let require number be 840 K + 2 which is multiple of 13.
Least value of K for which (840 K + 2) is divisible by 13 is K = 3
∴ Require Number = 840  3 + 2 = 2520 + 2 = 2522.
Hence option [D] is correct answer
Let require number be 840 K + 2 which is multiple of 13.
Least value of K for which (840 K + 2) is divisible by 13 is K = 3
∴ Require Number = 840  3 + 2 = 2520 + 2 = 2522.
Hence option [D] is correct answer
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