find the value of x
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x=4 hoga eska answer.
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leelagetha:
how 2^8 came
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• 2^16/16^2 = 2^2x
=> 2^16/(2^4)^2 = 2^2x
• Using identity : (a^m)^n = a^mn, we get,
=> 2^16/2^(4 × 2) = 2^2x
=> 2^16/2^8 = 2^2x
• Now, using identity : a^m/a^n = a^(m-n)
=> 2^(16 - 8) = 2^2x
=> 2^8 = 2^2x
• Now, if a^m = a^n, then m = n -
=> 8 = 2x
=> x = 8/2
=> x = 4
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Thank you.. ;-)
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