Question

find the value of X, (7/12)^-4 × (7/12)^-3x =(7/12)^5.​

Answer 1

Answer:

$( \frac{7}{12} ) ^{ - 4} \times ( \frac{7}{12} ) ^{ - 3x} = ( \frac{7}{12} )^{5} \\ ( \frac{7}{12} )is \: commmon \: - 4 + ( - 3x) = 5 \\ - 4 - 3x = 5 \\ - 3x = 5 + 4 \\ - x = \frac{9}{3} \\ - x = 3 \\ x = - 3$