Question

find the value of x.7^2x+1/49=7^3

Answer 1

$7 {}^{2x} + \frac{1}{7 {}^{2} } = 7 {}^{3}$
log7^2x+log7^-2=log7^3
log7^2x.7^-2=log7^3
2x-2=3.

Answer 2

Answer:

sorry idk

Step-by-step explanation:

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