find the value of x (7/3)^-3 × (7/3)^10=(7/13)^2x+3 ( ^ ) power
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Answer:
Hints:
(7/3)^-3 = (3/7)^3 = 3^3/7^3
(7/3)^10=7^10/3^10
When we multiply the resultant is 7^7/3^7
Process:
(7/3)^2x+3=(7/3)^7
Bases are equal,
Then powers are also equal.
2x+3=7
2x=4
x=2
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