Math, asked by ustatbrar, 9 months ago

find the value of x (7/3)^-3 × (7/3)^10=(7/13)^2x+3 ( ^ ) power​

Answers

Answered by ujwalmithraclass6
1

Answer:

Hints:

(7/3)^-3 = (3/7)^3 = 3^3/7^3

(7/3)^10=7^10/3^10

When we multiply the resultant is 7^7/3^7

Process:

(7/3)^2x+3=(7/3)^7

Bases are equal,

Then powers are also equal.

2x+3=7

2x=4

x=2

Similar questions