Find the value of ; [x-a] cube + [x-b]cube +[x-c] cube -3 [x-a] [x-b] [x-c]
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(x–a)³+(x–b)³+(x–c)³–3(x–a)(x–b)(x–c)
=3(a²+b²+c²–ab–bc–ca)x+3abc–(a³+b³+c³)
=3(a²+b²+c²–ab–bc–ca)x+3abc–(a³+b³+c³)
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