find the value of x and y
1. 2x+3y=8,x-2y=3
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2x + 3y = 8, x - 2y = 3 by elimination method.
2x + 3y = 8 . . . . (1)
x - 2y = 3 . . . . . (2)
Multiply equation (2) by 2, we get
2x + 3y = 8 . . . . (3)
2x - 4y = 6 . . . . . (4)
Adding (3) and (4) we get,
2x + 3y = 8
2x - 4y = 6
(-) (+) (-)
__________
7y = 2
y = 2/7
Substituting the value of y = 2/7 in equation (1) we get,
2x + 3y = 8
➞ 2x + 3(2/7) = 8
➞ 2x + 6/7 = 8
➞ 2x = 8 - 6/7
➞ 2x = 56 - 6/7
➞ 2x = 50/7
➞ x = 50/7 × 1/2
➞ x = 25/7
∴ The value of x = 25/7, y = 2/7 is the solution of the system of the given equations.
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