If a = 2, b = – 3, c = – 1, Find the value of
i) 3a + 5b – 2c
ii) a³ + b³ + c³ – 3abc
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If a = 2, b = – 3, c = – 1,
i ) 3a + 5b - 2c
=> 3(2) + 5(-3) - 2(-1)
=> 6 + -15 + 2
= > -7
ii ) a³ + b³ + c³ - 3abc
=> (2)³ + (-3)³ + (-1)³ - 3(2)(-3)(-1)
=> 8 + -27 + -1 - 18
=> -38
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