find the value of x and y
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y=180-53
=127°
x=180-(180-(53+53))
=180-74
=106°
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If the given lines are parallel,
AC is a transversal. So,
angle AED=angle ACB
so, angle ACB=53°
y=360-53=307°
angle BAC=53°, angle ACB=53°
so, angle ABC=180-(53+53)
=180-106=74°
x=180-74=106° (because it is a linear pair)
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