Math, asked by ak9097, 9 months ago

find the value of x and y​

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Answered by Parulsinghal
14

Step-by-step explanation:

1) In parallelogram ABCD ABllCD

ABC = y (alternate angles)

y = 60°

ABC = 60° we know that opp. angles of parallelogram is equal so.

ABC = ADC = 60

NOW = x + ADC = 180° (linear pair)

x = 180-60 = 120°

{\boxed{\mathcal\red{\fcolorbox{blue}{lawngreen}{x = 120° and y = 60°\:}}}}

2) In parallelogram ABCD

in Triangle AOD

AOD =180-100 (Linear pair)

AOD = 80°

NOW AOD + DAO +ADO = 180(ASP)

80+40+y = 180

y = 180-120 = 60°

angle BDC = ABD ( alternate angles)

BDC = 50°

so in traingle DOC

DOC + x + ODC = 180(ASP)

100 + x + 50 = 180

x = 180-150 = 30°

{\boxed{\mathcal\red{\fcolorbox{red}{lawngreen}{x = 30° And y = 60°\:}}}}

3) In parallelogram ABCD

ABC = 80° (corresponding angles)

ABC =x (VOA)

x =80°

ADC = 80°(alternate angles)

ADC + y = 180(linear pair)

y =180-80

y =100°

{\boxed{\mathcal\red{\fcolorbox{red}{lawngreen}{x = 80° and y = 100°\:}}}}

I have attached the figure of (3) becoz there is no labelling

thank you

hope it helps ❤️❤️

plz mark it as brainliest

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