find the value of x and y 2/x+3/y=4 and 4/x-3/y =5
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we have to find x and y
so,
2/x+3/y=4, 4/x-3/y=5
let 1/x =a and 1/y=b
so 2a+3b=4 and 4a-3b=5
now, solving both equation by elimination method
multiply equation 2a+3b=4 by 2
we have, 4a+6b=8
subtracting 4a-3b=5 from 4a+6b=8
we have,
4a+6b=8
4a-3b=5
(-) (+) (-)
__________
9b=3
b=3/9 b=1/3
putting b in 4a-3b =5
we have, a=3/2
1/x=a so a = 3/2
1/y=b so b=3
doing reciprocal
x=2/3 and y=1/3
This is your answer
I hope this will help you
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