find the value of x and y
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we have,
x−3y=3x−1=2x−y
Then,
x−3y=3x−1and3x−1=2x−y
x−3y−3x+1=0
−2x−3y+1=0
2x+3y−1=0…… (1)
Now,
3x−1=2x−y
3x−1−2x+y=0
x+y−1=0 …… (2)
By equation (1) and (2) to and we get,
2x+3y−1=0
(x+y−1=0)×2
Subtracting we get,
y+1=0
y=−1
Put the value of y in equation (2) and we get,
x=2
Hence, (x,y)=(2,−1) is the answer.
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