Question

Find the value of x and y:
9/(x+1) - 8/(y-1)=1, 3/(x+1)+ 4/(y-1)=2

Answer 1

Answer:

x=2

y=5

Step-by-step explanation:

hope it will help u

Answer 2

Answer:

x = 2 , y = 5

Solution:

The given equations in two variables are :

9/(x+1) - 8/(y-1) = 1 -------(1)

3/(x+1) + 4/(y-1) =2 ------(2)

Now,

Multiplying both sides of eq-(2) , we get ;

=> 2•[ 3/(x+1) + 4/(y-1) ] = 2•2

=> 2•3/(x+1) + 2•4/(y-1) = 2•2

=> 6/(x+1) + 8/(y-1) = 4 ------(3)

Now,

Adding eq-(1) and (3) , we have ;

=> 9/(x+1) - 8/(y-1) + 6/(x+1) + 8/(y-1) = 1 + 4

=> (9+6)/(x+1) = 5

=> 15/(x + 1) = 5

=> (x + 1)/15 = 1/5 { reciprocal both sides }

=> x + 1 = 15/5

=> x + 1 = 3

=> x = 3 - 1

=> x = 2

Now,

Putting x = 2 in eq-(2) , we get ;

=> 3/(x+1) + 4/(y-1) =2

=> 3/(2+1) + 4/(y-1) = 2

=> 3/3 + 4/(y-1) = 2

=> 1 + 4/(y-1) = 2

=> 4/(y-1) = 2 - 1

=> 4/(y-1) = 1

=> (y-1)/4 = 1 { reciprocal both sides }

=> y - 1 = 4

=> y = 4 + 1

=> y = 5

Hence,

The required values of x and y are 2 and 5 respectively.