Question

find the value of x and y by subsitutional method

Answer 1

HOLA

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$\frac{3x}{2} - \: \frac{5y}{3} = \: - 2 \: = > \: 9x \: - \: 10y \: + \: 12 \: = 0 \\ \\ \frac{x}{3} \: + \: \frac{y}{2} = \: \frac{13}{6} = 0 \: = > \: 2x \: + \: 3y \: - \: 13 \: \: = \: 0 \\ \\ from \: 2 \: we \: get \: y \: = \: \frac{13 \: - \: 2x}{3} \\ \\ substiuting \: y \: = \: \frac{13 \: - \: 2x}{3} we \: get \\ \\ 9x \: - \: \frac{10(13 \: - \: 2x)}{3} \: + \: 12 \: = \: 0 \\ \\ 27x \: - \: 10(13 \: - \: 2x) \: + \: 36 \: = \: 0 \\ \\ 27x \: - \: 130 \: + \: 20x \: + \: 36 \: = \: 0 \\ \\ 47x \: - \: 94 \: = \: 0 \: = > \: 47x \: = \: 94 \\ \\ x \: = \: \frac{94}{47} = \: 2 \\ \\ substiuting \: x \: = \: 2 \: in \: 1 \: we \: have \\ \\ 9 \: \times \: 2 \: - \: 10y \: + \: 12 \: = \: 0 \\ \\ 10y \: = \: 30 \: = > \: y \: = \: \frac{30}{10} = \: 3 \\ \\ so \: x \: = \: 2 \: and \: y \: = \: 3$

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