Question

. Find the value of x and y from the equation 2x+3y=8 and x-2y+3=0 x=2 and y=1 x=1 and y=-2 x=-1 and y=-2 x=1 and y=2

Answer 1

ANSWER

Given 2x+3y=8 ......... (1)

x+2y=5 ........... (2)

From (1), we have x=

2

8−3y

............ (3)

From (2), we have x=5−2y .......... (4)

Now, comparing the value of x, we get

2

8−3y

=5−2y

or 8−3y=10−4y

or 4y−3y=10−8

or y=2

Using y=2 in (4), x=5−2×2=1.

Answer 2

Given:

2x + 3y = 8 and x - 2y + 3 = 0

To find:

Find the value of x and y from the equation given.

Solution:

From given, we have,

2x + 3y = 8 and x - 2y + 3 = 0

⇒

2x + 3y = 8 ........(1)

x - 2y = -3 .........(2)

(1) - 2 × (2) gives,

2x + 3y = 8

2x - 4y = -6

7y = 14

y = 2

substituting the value of y in equation (1), we get,

2x + 3(2) = 8

2x + 6 = 8

2x = 8 - 6 = 2

x = 1

x=1 and y=2 is the correct answer.